Good thing that ain’t an english teacher
iHave a Lovesick Teacher
Submitted 3 hours ago by nutbutter@discuss.tchncs.de to [deleted]
https://discuss.tchncs.de/pictrs/image/dd1f8577-6bbc-477e-a0d8-b43f55c66232.jpeg
Comments
Grail@multiverse.soulism.net 1 hour ago
ArbitraryValue@sh.itjust.works 2 hours ago
You don’t need calculus to do this. Neither one is accelerating, so just calculate the velocity of one in the reference frame of the other by subtracting the vectors: from the point of view of the boy, the girl’s velocity vector has a component of -5 ft/sec north and 1 ft/sec east, so the magnitude is 26^0.5 ft/sec.
rustydrd@sh.itjust.works 23 minutes ago
I guess the calculus portion of this is to write the separation as a function of time, s = √26*t, and then realize that the “speed” of separation is the same regardless of time, because the first derivative is a constant.
Mirodir@discuss.tchncs.de 55 minutes ago
The “5 seconds after they started moving” is relevant. If we assume this takes place on Earth (i.e. on the surface of a sphere with a set pair of north/south poles), the angle between the two vectors changes depending on their current position.
If it’s not on the equator, it’s also slightly up to interpretation if “Due East” means they’ll turn to stay on the same latitude, always adjusting to stay moving east forever or if they’ll do a great circle. In the former case, the north moving one will eventually get stuck at the north-pole too instead of continuing their circle around the globe. Most likely not within 5 seconds though, unless the place they started was within 25 feet of the north-pole.
To actually do the math we’ll need to know (or somehow deduce) where “the place where everything about them began” is though.
ooterness@lemmy.world 3 hours ago
At any given time T, the coordinates form a right triangle with legs of length 5T and T. Therefore the distance D is given by D^2 = (5T)^2 + T^2 = 26T^2. This simplifies to D = T * sqrt(26). Therefore the rate of separation is sqrt(26) ft/sec regardless of time
farmgineer@nord.pub 3 hours ago
Shouldn’t it be ‘after having been together’?
What is ‘at the same time’ referring to in that sentence? They wanted to break up at the same time (as in both had the idea)? They wanted to break up at the same time on the clock to continue the theme of things being same-y?
The boy is due north of what? The place? The girl? Also, the girl should be wondering about her decision, I think.
(I don’t even speak English every day anymore, so I could be wrong).
Bonsoir@lemmy.ca 3 hours ago
They said goodbye at a given position and are then leaving each in a different direction. They are starting to move at the same time from the same point.
NoSpotOfGround@lemmy.world 2 hours ago
Wait, we know their position exactly? That means we have no idea what their velocities are!
Actually, their velocities are specified precisely in the problem description.
What? Velocity too? Now we know nothing!!
misericordiae@literature.cafe 1 hour ago
(I don’t even speak English every day anymore, so I could be wrong).
You’re not wrong. I think some of it is the difference between casual speech and formal writing (people are more likely to say “after being” but write “after having been”, especially in published work)**, but some of it is also just poorly phrased. It makes enough sense to a native speaker to get what the problem is asking, though.
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** I think the first may be correct in some cases, but idk the rule.
farmgineer@nord.pub 28 minutes ago
It only bothered me because I saw that it was a school assignment and I thought it would be to a higher standard. In casual speech, I don’t really care unless the meaning is unclear.
FinjaminPoach@lemmy.world 3 hours ago
Sigh i miss high school maths. Even i’m lovesick now.
Jankatarch@lemmy.world 2 hours ago
Reminds me that one exurb1a pinecone video.
trxxruraxvr@lemmy.world 2 hours ago
They probably would have stayed together if they had just had the sense to use SI units.