-3 id the hidden character of the solution, like evil ryu or devil jin.
teachings
Submitted 8 months ago by fossilesque@mander.xyz to science_memes@mander.xyz
https://mander.xyz/pictrs/image/7a77a0d9-bf97-4b35-aa7a-8ab42497c005.jpeg
Comments
namelivia@lemmy.world 8 months ago
lseif@sopuli.xyz 8 months ago
just a glimpse into my dark and twisted mind
ZILtoid1991@lemmy.world 8 months ago
But for the Joker, that’s the real solution.
Gemini24601@lemmy.world 8 months ago
Doesn’t x also -3?
dankestnug420@lemmy.ml 8 months ago
Sqrt(9)
UnRelatedBurner@sh.itjust.works 8 months ago
Uhm, actually 🤓☝️!
Afaik sqrt only returns positive numbers, but if you’re searching for X you should do more logic, as both -3 and 3 squared is 9, but sqrt(9) is just 3.
If I’m wrong please correct me, caz I don’t really know how to properly write this down in a proof, so I might be wrong here. :p
(ps: I fact checked with wolfram, but I still donno how to split the equation formally)Evil_Shrubbery@lemm.ee 8 months ago
Fund the sqrter!
Kusimulkku@lemm.ee 8 months ago
Sqrt
hehe
Crashumbc@lemmy.world 8 months ago
Also math teacher…
“Show your work”
merari42@lemmy.world 8 months ago
Middle school math memes
xkforce@lemmy.world 8 months ago
The number of solutions/roots is equal to the highest power x is raised to (there are other forms with different rules and this applies to R and C not higher order systems)
Some roots can be complex and some can be duplicates but when it comes to the real and complex roots, that rule generally holds.
GnomeKat@lemmy.blahaj.zone 8 months ago
I think you can make arbitrarily complicated roots if you move over to G^n^ which includes the R and C roots…
For example
(3e1e2e3e4)^2 = 9in G^4^, complex roots are covered becausee1e2^2 = -1making it identical toiso G^n^ (n>=2) includes C.G^n^ also includes all the vectors so any vector with length 3 will square to 9 because
u^2 = u dot u = |u|^2ouRKaoS@lemmy.today 8 months ago
You lost me at “arbitrarily complicated,” sorry.
MBM@lemmings.world 8 months ago
I thought this would be related to quaternions, octonions etc. but no, it’s multivectors and wedge products. Very neat, I didn’t know you could use them like that.
someacnt_@lemmy.world 8 months ago
Then you can extend to arbitrary algebra
Beetschnapps@lemmy.world 8 months ago
To translate: As a child learning math this means “ignore math, the explanations don’t explain anything real, they only explain math. So instead focus on language and the arts.”
overcast5348@lemmy.world 8 months ago
I’m guessing that you were one of those “I won’t ever use all this math” kind of students?
Maalus@lemmy.world 8 months ago
Or you were just shit at maths and don’t have any idea how useful it is because you avoid it like the plague.
space@lemmy.dbzer0.com 8 months ago
My teacher explained as sqrt(poop^2) = abs(poop). Yes, he wrote poop on the blackboard.
NeatNit@discuss.tchncs.de 8 months ago
He should have drawn a pile of poop instead 💩 (preferably without a face)
Patrizsche@lemmy.ca 8 months ago
Me, a statistician: “if chi-square equals 9 then chi equals 3… What??”
Sweetpeaches69@lemmy.world 8 months ago
Oh, I know this one! It’s pi!
jol@discuss.tchncs.de 8 months ago
What, no. It’s… Eh close enough.
Reddfugee42@lemmy.world 8 months ago
TAU IS BETTER
/obligatory
mexicancartel@lemmy.dbzer0.com 8 months ago
Help how do i take factorial of pi
hemko@lemmy.dbzer0.com 8 months ago
-3 = 3
mexicancartel@lemmy.dbzer0.com 8 months ago
Adding 3 on both sides
3-3=3+3
0 = 6
1•0 = 6
1 = 6/0
1 = inf
Multiplying e^(iπ) on both sides,
e^(iπ) = - inf
iπ = ln|-inf|
π = ln|-inf| ÷ i
hemko@lemmy.dbzer0.com 8 months ago
I gotta say half of that goes over my head, but I raise my hat to you
ech@lemm.ee 8 months ago
Absolutely.
bleistift2@feddit.de 8 months ago
This only every got handed down to us as gospel. Is there a compelling reason why we should accept that (-3) × (-3) = 9?
notabot@lemm.ee 8 months ago
You can look at multiplication as a shorthand for repeated addition, so, for example:
3x3=0 + 3 + 3 + 3 = 9In other words we have three lots of three. The zero will be handy later…
Next consider:
-3x3 = 0 + -3 + -3 + -3 = -9Here we have three lots of minus three. So what happens if we instead have minus three lots of three? Instead of adding the threes, we subtract them:
3x-3 = 0 - 3 - 3 - 3 = -9Finally, what if we want minus three lots of minus three? Subtracting a negative number is the equivalent of adding the positive value:
-3x-3 = 0 - -3 - -3 - -3 = 0 + 3 + 3 + 3 = 9Do let me know if some of that isn’t clear.
bleistift2@feddit.de 8 months ago
This was very clear. Now that I see it, I realize it’s the same reasoning why x^(-3) is 1/(x^3):
2 × -3 = -6 1 × -3 = -3 0 × -3 = 0 -1 × -3 = +3
affiliate@lemmy.world 8 months ago
i think this is a really clean explanation of why (-3) * (-3) should equal
9. i wanted to point out that with a little more work, it’s possible to see why (-3) * (-3) must equal 9. and this is basically a consequence of the distributive law:0 = 0 * (-3) = (3 + -3) * (-3) = 3 * (-3) + (-3) * (-3) = -9 + (-3) * (-3).
the first equality uses
0 * anything = 0. the second equality uses(3 + -3) = 0. the third equality uses the distribute law, and the fourth equality uses3 * (-3) = -9, which was shown in the previous comment.so, by adding
9to both sides, we get:9 = 9 - 9 + (-3) * (-3).in other words,
9 = (-3) * (-3). this basically says that if we want the distribute law to be true, then we need to have (-3) * (-3) = 9.it’s also worth mentioning that this is a specific instance of a proof that shows
(-a) * (-b) = a * bis true for arbitrary rings. (a ring is basically a fancy name for a structure with addition and distribute multiplication.) so, any time you want to have any kind of multiplication that satisfies the distribute law, you need (-a) * (-b) = a * b.in particular,
(-A) * (-B) = A * Bis also true whenAandBare matrices. and you can prove this using the same argument that was used above.
Davel23@fedia.io 8 months ago
Same reason that a double negative makes a positive.
ImplyingImplications@lemmy.ca 8 months ago
Here’s a other example:
A) -3 × (-3 + 3) = ?
You can solve this by figuring out the brackets first. -3 × 0 = 0
You can also solve this using the distributive property of multiplication, rewriting the equation as
A) -3 × (-3 + 3) = 0 (-3 × -3) + (-3 × 3) = 0 (-3 × -3) - 9 = 0 (-3 × -3) = 9
If (-3 × -3) didn’t equal 9 then you’d get different answers to equation A depending on what method you used to solve it.
Maggoty@lemmy.world 8 months ago
I know the math but I still feel like I’m out of the loop somehow?
kszeslaw@szmer.info 8 months ago
(-3)^2 = 9 as well
JackbyDev@programming.dev 8 months ago
There’s nothing more to this than linking the star wars quote to the -3. That’s it lol
Maggoty@lemmy.world 8 months ago
Oh okay. Don’t mind me trying to over analyze things.
Neato@ttrpg.network 8 months ago
-3 feels like cheating.
ech@lemm.ee 8 months ago
Eh, not really. It’s been a while, but I’m pretty sure the rule in algebra when solving for a squared variable like this is to use ± for exactly that reason.
knorke3@lemm.ee 8 months ago
just wait for roots of imaginary numbers :)