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Conversing with Mathematicians

⁨391⁩ ⁨likes⁩

Submitted ⁨⁨9⁩ ⁨months⁩ ago⁩ by ⁨fossilesque@mander.xyz⁩ to ⁨science_memes@mander.xyz⁩

https://mander.xyz/pictrs/image/a25883e1-08bc-4293-affd-6e3e1f666d21.webp

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  • pr06lefs@lemmy.ml ⁨9⁩ ⁨months⁩ ago

    What about plain old x = -10?

    -10 ^ 2 = 100 -10 ^ 3 = -1000 -10 ^ 5 = -100000

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    • Redacted@lemmy.world ⁨9⁩ ⁨months⁩ ago

      Isn’t that the joke?

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    • Enkers@sh.itjust.works ⁨9⁩ ⁨months⁩ ago

      That’s what he wrote, I imagine.

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      • Siethron@lemmy.world ⁨9⁩ ⁨months⁩ ago

        It is, but with imaginary numbets

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    • JackbyDev@programming.dev ⁨9⁩ ⁨months⁩ ago

      i² = -1 so…

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    • thedudeabides@lemmy.dbzer0.com ⁨9⁩ ⁨months⁩ ago

      Nothing gets past you eh?

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      • pr06lefs@lemmy.ml ⁨9⁩ ⁨months⁩ ago

        people being pedantic showoffs doesn’t really register as humor for me, TBH

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    • dwindling7373@feddit.it ⁨9⁩ ⁨months⁩ ago

      10 * i^2 is -10.

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      • Abracadaniel@hexbear.net ⁨9⁩ ⁨months⁩ ago

        of course, but this problem is solvable without any understanding of complex numbers, and 10*i^2 is a really clunky, multi-operation expression whereas -10 is just an integer.

        simplifying one’s answers is standard practice and any grader who received the answer in the OP would be obligated to point out that while technically correct, they’re missing the basic fact that the answer is -10.

        The Rube Goldberg comment is apt as the solution is absurdly complicated and overengineered for the task it performs.

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    • aaaaaaadjsf@hexbear.net ⁨9⁩ ⁨months⁩ ago

      Yeah exactly you’re right, why overcomplicate the problem like the Reddit comment did? I guess that’s just typical Reddit thinking that being pendantic and using lots of fancy words and long explanations makes you smart.

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      • Krauerking@lemy.lol ⁨9⁩ ⁨months⁩ ago

        Nah just boiler plate autism.

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    • Deconceptualist@lemm.ee ⁨9⁩ ⁨months⁩ ago

      That was my immediate thought too.

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    • Sphks@lemmy.dbzer0.com ⁨9⁩ ⁨months⁩ ago

      Boooooring

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  • Deebster@programming.dev ⁨9⁩ ⁨months⁩ ago

    When all you have is an imaginary hammer, everything looks like a rotation around the imaginary unit circle.

    Explanation of maths

    x = -10, i = √-1 so i² = -1 and 10i²=-10

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    • MonkderVierte@lemmy.ml ⁨9⁩ ⁨months⁩ ago

      Found the math but no explanation.

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      • JackbyDev@programming.dev ⁨9⁩ ⁨months⁩ ago

        The squareroot of 100 is ±10.

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    • fx3@beehaw.org ⁨9⁩ ⁨months⁩ ago

      IIRC, your spoilery “so” is the other way round. The right side is the definition, and the left-hand side a layman’s shorthand, as the root operator isn’t defined on negative numbers.

      I might very well be wrong. My being a mathematician has been over for a while now, my being a pedantic PITA not though.

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      • Deebster@programming.dev ⁨9⁩ ⁨months⁩ ago

        I don’t know enough to know how correct your pedantry is (technically or not), but to explain the meme it made sense to go through the symbols in the order you see them. I never got any points from the proof questions in exams anyway.

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  • NigelFrobisher@aussie.zone ⁨9⁩ ⁨months⁩ ago

    Wait, isn’t x just -10 if x^3 is not 1000?

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    • bi_tux@lemmy.world ⁨9⁩ ⁨months⁩ ago

      yes, it is

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  • iAvicenna@lemmy.world ⁨9⁩ ⁨months⁩ ago

    that is a very long way to write -10

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  • Yaysuz@lemm.ee ⁨9⁩ ⁨months⁩ ago

    What an extremely unnecessary explanation. As a math teacher I would have deducted points for this answer.

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    • androogee@midwest.social ⁨9⁩ ⁨months⁩ ago

      “show your work”

      Malicious compliance intensifies

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    • Razzazzika@lemm.ee ⁨9⁩ ⁨months⁩ ago

      Unless I was in that clas where we had to write mathematical proofs. I HATED those. Sure, you solved the question but write out this complicated reason for why your answer is the correct answer.

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  • southsamurai@sh.itjust.works ⁨9⁩ ⁨months⁩ ago

    My brain

    It hurts

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    • Cryophilia@lemmy.world ⁨9⁩ ⁨months⁩ ago

      That’s because the explanation was about 10 times as complicated as it needs to be

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      • olafurp@lemmy.world ⁨9⁩ ⁨months⁩ ago

        Math pun intended?

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    • mexicancartel@lemmy.dbzer0.com ⁨9⁩ ⁨months⁩ ago

      He is trolling with overcomplicating

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  • Ravi@feddit.org ⁨9⁩ ⁨months⁩ ago

    No definition what values are suitable for x.

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    • quicksand@lemm.ee ⁨9⁩ ⁨months⁩ ago

      x has to be -10, right? Or am I missing something?

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      • jacksilver@lemmy.world ⁨9⁩ ⁨months⁩ ago

        Yeah, I think the point is that the person answering was wrong/over complicating. If x=10i, then x^2 would be -100 (or potentially -10 depending on what you think the ^2 is applied to).

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      • Ravi@feddit.org ⁨9⁩ ⁨months⁩ ago

        Depends on what are the allowed values for x are. Real numbers, complexe numbers, binary or I made up my own numbers ;)

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      • WolfLink@sh.itjust.works ⁨9⁩ ⁨months⁩ ago

        The answer in the meme (10i^2) is -10

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      • Malgas@beehaw.org ⁨9⁩ ⁨months⁩ ago

        Probably what they were going for, but there are literally an infinite number of exotic arithmetic spaces you could ask this question in. For example, x=10 works in any ring with a modulus greater than 100 and less than 1000.

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  • Xavienth@lemmygrad.ml ⁨9⁩ ⁨months⁩ ago

    Therefore i¹⁰ = ln(-1)¹⁰/pi¹⁰ = -1

    This is true but does not follow from the preceding steps, specifically finding it to be equal to -1. You can obviously find it from i²=-1 but they didn’t show that. I think they tried to equivocate this expression with the answer for e^(iπ) which you can’t do, it doesn’t follow because e^(iπ) and i¹⁰ = ln(-1)¹⁰/pi¹⁰ are different expressions and without external proof, could have different values.

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    • Dalvoron@lemm.ee ⁨9⁩ ⁨months⁩ ago

      If we know the values of ln(-1)¹⁰ and pi¹⁰ we hypothetically could calculate their divided result as -1 instead of using strict logic, but it is missing a few steps. Moreover logs of negative numbers just end up with an imaginary component anyway so there isn’t really any progress to be made on that front. Typing ln(-1)¹⁰ into my scientific calculator just yields i¹⁰pi¹⁰, (I’m guessing stored rather than calculated? Maybe calculated with built in Euler) so the result of division is just i¹⁰ anyway and we’re back where we started.

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      • Xavienth@lemmygrad.ml ⁨9⁩ ⁨months⁩ ago

        You can find the value of ln(-1)¹⁰ by examining the definition of ln(x): the result z satisfies eᶻ=x. For x=-1, that means the z that satisfies eᶻ=-1. Then we know z from euler’s identity. Raise to the 10, and there’s our answer. And like you pointed out, it’s not a particularly helpful answer.

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  • MonkderVierte@lemmy.ml ⁨9⁩ ⁨months⁩ ago

    Can someone write this in Python, please?

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    • TexasDrunk@lemmy.world ⁨9⁩ ⁨months⁩ ago

      import math

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