No. F=GMm/d2. The mass of the earth doesn’t change so g=GM/d2 will not change
Comment on Falling
JohnDClay@sh.itjust.works 1 year ago
Does the bowling ball ever so slightly increase the gravitational constant because of it’s greater mass? Is that what the right guy is getting at?
hddsx@lemmy.ca 1 year ago
Tar_alcaran@sh.itjust.works 1 year ago
Ah but the earth doesn’t just attract the ball or feather. The bowling ball attracts the earth as well, and since it has more mass, it will pull the earth towards it faster than the feather.
But if you drop them at the same time, that’s moot.
hddsx@lemmy.ca 1 year ago
In other words, the feather and ball are both attracted to the earth at the same rate but because the ball has a higher mass, the earth is very slightly more attracted to the ball
Honytawk@lemmy.zip 1 year ago
Maybe the ball is just more of their type?
JohnDClay@sh.itjust.works 1 year ago
So why does the bowling ball fall faster in a vacuum? Does it appear faster locally because the heavier object makes local time slower than the lighter object compared to a distant observer? I’m trying to understand what the meme is getting at.
Tja@programming.dev 1 year ago
That’s the neat thing: it doesn’t
Drewfro66@lemmygrad.ml 1 year ago
The bowling ball also pulls the earth towards itself. This amount is imperceptibly small but still there
hddsx@lemmy.ca 1 year ago
I’m trying to understand as well.
dev_null@lemmy.ml 1 year ago
Because it, ever so slightly, pulls Earth towards it with it’s own, miniscule gravity.
JohnDClay@sh.itjust.works 1 year ago
But that doesn’t make the bowling ball fall faster to a distant observer, just the earth fall twords the ball. To an observer on earth it would appear to fall faster though.
itsnotits@lemmy.world 1 year ago
because of its* greater mass
dream_weasel@sh.itjust.works 1 year ago
The gravitational constant G, no, the mutual gravitational force between the earth and the ball approximated as g, yes.
Faresh@lemmy.ml 1 year ago
But how would that make the bowling ball fall faster? F = G × m₁ × m₂ / r² and F = m₁ × a ⇒ a = F / m = G × m₂ / r², where m₁ is the mass of the ball and m₂ the mass of the planet. So the gravitational acceleration of a bowling ball is independent of its mass.
Zehzin@lemmy.world 1 year ago
I guess the bowling ball attract the earth towards it, shortening the distance which from the bowling ball’s perspective means it’s faster