Water doesn’t compress (for all intents and purposes), so no. I.E. the water pressure of the ocean would indeed push inward against the balloon much more strongly, but the water inside the balloon would push back by the same amount.
Nothing special would happen if you pop the balloon, the rubber would just rapidly contract, basically the same as it would above the surface.
nooneescapesthelaw@mander.xyz 3 days ago
Let’s first state our assumptions:
Very thin membrane, the balloon skin cannot be compressed more than it already is
Zero trapped air
Isothermal conditions, water temperature at the bottom of the ocean is the same as the top, that way we don’t need to deal with thermal expansion
Balloon is a perfect sphere
Calculations:
Pressure on the balloon is densitygravitydepth ~= 100010100 = 1 Mpa or 10 atmospheres
The bulk modulus of water is 2.2 Gpa so (change in volume)/(initial volume) = (change in pressure)/(bulk modulus) = 0.0046% decrease in volume
0.0046% decrease in volume is like a 0.015% decrease in radius
magnetichuman@fedia.io 3 days ago
is there a /m/theydidthemath ?
_NetNomad@fedia.io 2 days ago
/m/theydidthemonstermath