This can’t actually work if the floor is a level plane right?
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milicent_bystandr@lemm.ee 1 week agoDoes it require any arbitrary constraints on the topography of the floor?
jaybone@lemmy.world 1 week ago
milicent_bystandr@lemm.ee 1 week ago
Right. Somehow I was thinking only of the floor being uneven, not the table legs. Surely it’s trivial to have table legs sufficiently different to not fit on any arbitrary shape of floor?
jaybone@lemmy.world 1 week ago
Haha yes :) I was somehow thinking for this type of problem, the usual case is the legs are uneven… because if the floor is uneven or not level the table will be uneven or not level regardless of whether it has 0, 1, or n legs. But I guess the problem is about “wobbling” not about being level.
milicent_bystandr@lemm.ee 1 week ago
If the table has three legs it will be stable on any floor no matter how uneven (up to some limit!). Won’t be perfectly flat, but won’t wobble.
jol@discuss.tchncs.de 1 week ago
Yes, the floor has to be bigger than the chair.
milicent_bystandr@lemm.ee 1 week ago
Oh dear. Usually the chair is so big it stands way above the floor.
Mirodir@discuss.tchncs.de 1 week ago
Sorta. The function height(angle) needs to be continuous. From there it’s pretty clear why it works you know the mean value theorem.
frank@sopuli.xyz 1 week ago
Yeah, I guess the assumption it takes is that there aren’t larger topographic changes for the other legs between their points, and that the legs are equal length. But I like it, it’s a fun one I’m trying next time
milicent_bystandr@lemm.ee 1 week ago
So we assume a perfect table on an imperfect floor?
Sounds like a theological allegory.