yetAnotherUser

@yetAnotherUser@discuss.tchncs.de

• ⁨Comment⁩ on ⁨I just cited myself.⁩ ⁨⁨4⁩ ⁨days⁩ ago⁩:

  Yes, but similar flaws exist for your proof.

  The algebraic proof that 0.999… = 1 must first prove why you can assign 0.999… to x.

  My “proof” abuses algebraic notation like this - you cannot assign infinity to a variable. After that, regular algebraic rules become meaningless.

  The proper proof would use the definition that the value of a limit approaching another value is exactly that value. For any epsilon > 0, 0.999… will be within the epsilon environment of 1 (= the interval 1 ± epsilon), therefore 0.999… is 1.

• ⁨Comment⁩ on ⁨I just cited myself.⁩ ⁨⁨4⁩ ⁨days⁩ ago⁩:

  Unfortunately not an ideal proof.

  It makes certain assumptions:

  1. That a number 0.999… exists and is well-defined
  2. That multiplication and subtraction for this number work as expected

  Similarly, I could prove that the number which consists of infinite 9’s to the left of the decimal is equal to -1:

  ...999 = x
  ...990 = 10x
  
  Calculate x - 10x:
  
  x - 10x = ...999 - ...990
  -9x = 9
  x = -1
  

  And while this is true for 10-adic numbers, it is certainly not true for the real numbers.

• ⁨Comment⁩ on ⁨Just saying⁩ ⁨⁨1⁩ ⁨week⁩ ago⁩:

  I can’t be racist because human races do not exist, I just hate certain ethnicities.

• ⁨Comment⁩ on ⁨A future sci-fi writers never could've imagined⁩ ⁨⁨2⁩ ⁨weeks⁩ ago⁩:

  Hey, wanna removed?😳