Comment on YEET

• finitebanjo@lemmy.world ⁨5⁩ ⁨months⁩ ago

  I think they were able to track it for at least 2 frames, thus calculate it’s speed.

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  • Klear@sh.itjust.works ⁨5⁩ ⁨months⁩ ago

    Nope, just one frame. Adds to the myth, when people don’t know the exact speed.

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    • CheeseNoodle@lemmy.world ⁨5⁩ ⁨months⁩ ago

      tbf the calculated speed is actually roughly the minnimum based on its starting position and the frame it appeared in. it could have actually been going even faster.

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      • Klear@sh.itjust.works ⁨5⁩ ⁨months⁩ ago

        Pretty sure that’s not really true though.

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    • finitebanjo@lemmy.world ⁨5⁩ ⁨months⁩ ago

      One frame before the blast and one frame after, but semantics.

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      • victorz@lemmy.world ⁨5⁩ ⁨months⁩ ago

        I don’t count having no visual indication of the object as “tracking” it, if we’re talking semantics. One frame could equal an even faster speed than what it would minimally take to cross the entire width of the image at some trajectory vector. For other vectors, it could be (much) less (like not passing straight through the image from on side to the opposite side, e.g.).

        It’s important to not hang too hard on this as the escape speed is dependent on air resistance, or rather lack thereof. Those escape speed numbers are defined along with the assumption of zero air resistance or other forces acting on the object.

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  • merc@sh.itjust.works ⁨5⁩ ⁨months⁩ ago

    It isn’t speed.

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    • victorz@lemmy.world ⁨5⁩ ⁨months⁩ ago

      lol what

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