Comment

calcopiritus@lemmy.world ⁨3⁩ ⁨weeks⁩ ago

This triangle is impossible.

If the distance between B and C is 0, B and C are the same points. If that is the case, the distances between A and B and A and C must be the same.

However, i ≠ 1.

If you want it to be real (hehe) the triangle should be like this:

    C
    | \
|i| |  \ 0
    |   \
    A---B
     |1|

Drawing that on mobile was a pain.

As the other guy said, you cannot have imaginary distances.

Also, you can only use Pythagoras with triangles that have a 90° angle. Nothing in the meme says that there’s a 90° angle. As I see it, there are only 0° and 180° angles.

Goodbye, I have to attend other memes to ruin.

source

Sort:hotnew top

thomasloven@lemmy.world ⁨3⁩ ⁨weeks⁩ ago
Context matters. In geometry i is a perfectly cromulent name for a real valued variable.

source
- Clinicallydepressedpoochie@lemmy.world ⁨2⁩ ⁨weeks⁩ ago
  Oh shit, he used the word cromulent. Every one copy off this guy.
  
  source
  - stevedice@sh.itjust.works ⁨2⁩ ⁨weeks⁩ ago
    That wouldn’t be cromulent, would it?
    
    source
Dayroom7485@lemmy.world ⁨3⁩ ⁨weeks⁩ ago
Mad mobile drawing!!

source
technocrit@lemmy.dbzer0.com ⁨2⁩ ⁨weeks⁩ ago

As the other guy said, you cannot have imaginary distances.

Incorrect. There are complex valued metric spaces.

And even if we assume real valued metrics, then i usually represents the unit vector (0,1) which has distance real 1.

source
- stevedice@sh.itjust.works ⁨2⁩ ⁨weeks⁩ ago
  That’s NOT a metric. That’s a measure. Two wholly different things.
  
  source
  - diaphanous@feddit.org ⁨2⁩ ⁨weeks⁩ ago
    It can be a pseudometric
    
    source
    stevedice@sh.itjust.works ⁨2⁩ ⁨weeks⁩ ago
    That’s more related to a metric but it still can’t be complex valued and it’s still not a measure.
    
    source
planish@sh.itjust.works ⁨2⁩ ⁨weeks⁩ ago
This is clearly meant to be a right triangle. And the distances between the points are the same (because the squares of the coordinate differences are the same), just the directions are different.

If you move 1 unit forward, turn the correct 90 degrees, and then move i units forward, you will end up back where you started.

source
- calcopiritus@lemmy.world ⁨2⁩ ⁨weeks⁩ ago
  You can’t have a distance in a “different direction”. That’s what the |x| is for, which is the modulus. If you rotate a triangle, the length of the sides don’t change.
  
  source
  - planish@sh.itjust.works ⁨2⁩ ⁨weeks⁩ ago
    The vector from one point to another in space has both a distance (magnitude) and a direction. Labeling the side with i only really makes sense if you say we’re looking at a vector of “i units that way”, and not at an assertion that these two points are a directionless i units apart. Then you’d have to break out the complex norms somebody mentioned.
    
    source
muntedcrocodile@lemm.ee ⁨2⁩ ⁨weeks⁩ ago
Isnt it fine to assume a 90° angle its just that when u square side AC ur multiplying by i which also represents a rotation by 90° so u now nolonger have a triangle?

source
- calcopiritus@lemmy.world ⁨2⁩ ⁨weeks⁩ ago
  It’s not fine to assume a 90° angle. The distance between B and C is 0. Therefore the angle formed by AB and AC is 0°.
  
  If the angle is 90°, then BC should be sqrt(2), not 0. Since the length of both sides is 1. sqrt(|i|^2+|1|^2) = sqrt(2).
  
  source
  - muntedcrocodile@lemm.ee ⁨2⁩ ⁨weeks⁩ ago
    So essentially what ur saying is. The imaginary and real arent 90° or pythagoras is only valid for real numbers?
    
    source