Given an infinite number of rooms and guests, it is highly likely both he and the boulder are already there.
I don’t follow. He’s clearly not there already, being at the switch instead of at the hotel.
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esc27@lemmy.world 4 months ago
Given an infinite number of rooms and guests, it is highly likely both he and the boulder are already there. So he should o to the hotel where he already is and has a room
Happy comes from hap, which is essentially luck. So happy can imply lucky or fortunate. If he gets to the hotel and finds he already is checked into his room in an otherwise full hotel, then he is indeed lucky and likely happy.
deranger@sh.itjust.works 4 months ago
kazren@lemmy.world 4 months ago
But if there are infinite guests, could he not have a reservation?
deranger@sh.itjust.works 4 months ago
Have to ask all current infinite reservations to move to <room number> x 2, now you’ve got 2x the open rooms as all current infinite reservations are even rooms only.
gmtom@lemmy.world 4 months ago
A hotel room being "full doesn’t necessarily mean the guest is in the room at that very moment, just that the room us reserved. And given infinite rooms it’s basically guaranteed one of those reservations is for sisyphus
deranger@sh.itjust.works 4 months ago
If he already had a reservation, being “full” wouldn’t be an issue. Since the potential of the hotel being full is given, we must assume he doesn’t have a reservation.
EmoDuck@sh.itjust.works 4 months ago
An infinite set doesn’t necessarily contain every number. And the Grand Hilbert Hotel is known for having a strict policy against Tartarus convict’s