I can’t tell if this is satire. If not, you say it doesn’t hurt to use too much, but I would say that a company would want to save all the money wasted on applying 20x the required amount…
Comment on More thermal paste = more heat dissipation, right?
Thorry@feddit.org 17 hours agoTrickDacy@lemmy.world 17 hours ago
Thorry@feddit.org 17 hours ago
[deleted]Washedupcynic@lemmy.ca 16 hours ago
Love how you ignored my response to your response that provided a scientific rationale demonstrating that you don’t have a clear understanding of how thermal paste works, and you just doubled down on flawed opinions. Carry on friend.
qprimed@lemmy.ml 15 hours ago
this has got to be a troll post. right? RIGHT?!
as you pointed out, just get rid of the air gaps with the absolute minimal amount of paste.
my back woods method
ensure your heat sink does not have pre-applied paste or a pad. apply a small amount of paste. cut the thickness with the short edge of an old credit card at about a 30° angle, using just enough pressure to bend the card slightly so the smooth surface of the card presses paste into voids and the trailing edge of the card removes excess to level the surface - you will likely still be able to make out some chip package markings through the paste. remove all edge excess and spillage. fit your heat sink. done.
TrickDacy@lemmy.world 16 hours ago
The perfect amount would be a very thin layer, evenly distributed with zero waste. This is very much not that. At best you could argue it’s a quick way to do it that is worth the trade-off, except for the valid point the other commenter made about too much actually reducing heat conduction.
Washedupcynic@lemmy.ca 17 hours ago
Optimal thermal paste thickness (bond-line thickness) is critical for heat dissipation. The layer should be thin, ideally between 25 µm and 50 µm, which is roughly the thickness of two sheets of standard paper. The paste’s sole purpose is to fill microscopic air pockets between the metal surfaces for better thermal conduction. Source, I spent 6 months in a laboratory experimenting with and producing thermal pastes and insulators. I spent days cutting and cleaning copper squares, applying the experimental pastes, and testing thermal conductivity via the application of Fourier’s Law of heat conduction.
Q = kA(Δ T/Δ X)
Where Q is heat flow, A is the cross-sectional area, and Δ x is the paste’s thickness.
Another source.
That’s way more paste than you need for 50 µm application.
Drops Mic
ZkhqrD5o@lemmy.world 16 hours ago
Did you say 50mm of thermal paste?
Washedupcynic@lemmy.ca 16 hours ago
Microns, not milimeters. One micron in 1/1000 of a milimeter.
ZkhqrD5o@lemmy.world 16 hours ago
Ah, my bad. 1000. So 50km of thermal paste?
foodandart@lemmy.zip 16 hours ago
I think he said 50m…
snooggums@piefed.world 15 hours ago
50 miles is too far for paste
DeadDigger@lemmy.zip 13 hours ago
To add to this to much is also a problem because it can trap air itself and create air pockets that way