turkey pot pies

Comments

• brisk@aussie.zone ⁨8⁩ ⁨months⁩ ago

  This meme does meat pies dirty (unless “mincemeat pie” is one of those horribly deceptive terms like “mince pie”)

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  • paholg@lemm.ee ⁨8⁩ ⁨months⁩ ago

    A mincemeat pie is another name for a mince pie. So yeah.

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    • usualsuspect191@lemmy.ca ⁨8⁩ ⁨months⁩ ago

      Mincemeat is not the same, at least where I’m from… Mincemeat is dried fruit and spices, no meat

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    • brisk@aussie.zone ⁨8⁩ ⁨months⁩ ago

      Then I take it back. I have never been as disappointed as the first time I was offered a “mince” pie

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  • multifariace@lemmy.world ⁨8⁩ ⁨months⁩ ago

    The more savory a pie gets, the more I like it. Pumpkin pie is okay. Mince meat is fine. Turkey is great!

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    • FuglyDuck@lemmy.world ⁨8⁩ ⁨months⁩ ago

      Pumpkin pie is the devil.

      But there is something amazing about chicken/turkey pot pies or other savory pies in that vein.

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  • HeyMrDeadMan@lemmy.world ⁨8⁩ ⁨months⁩ ago

    French meat pie (Tourtiere) was always my favorite part of family Thanksgiving.

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• southsamurai@sh.itjust.works ⁨8⁩ ⁨months⁩ ago

  They’ve never had a good mincemeat pie then.

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• Wilzax@lemmy.world ⁨8⁩ ⁨months⁩ ago

  How can a probability be the null set?

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• Leviathan@lemmy.world ⁨8⁩ ⁨months⁩ ago

  What’s going on here? Mincemeat pies are delicious.

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• randomsnark@lemmy.ml ⁨8⁩ ⁨months⁩ ago

  missed opportunity to mention to volume of a pizza pie with radius z and depth a

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• ryannathans@aussie.zone ⁨8⁩ ⁨months⁩ ago

  Theta minus sin theta? What does that give you

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  • TheOakTree@beehaw.org ⁨8⁩ ⁨months⁩ ago

    (1/2)×θ×r^2

    gives you the area of a sector circle, like a slice of pie.

    (1/2)×θ×side1×side2

    is the side-angle-side formula for the area of a triangle.

    We know that the triangle has two sides that are equal to the radius, so we replace side1×side2 with r^2. Since the area of the arc segment is equal to the area of a sector minus the triangle encompassed by the sector, we can subtract triangle area from sector area to get

    (1/2)×(θ-sin(θ))×r^2

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    • ryannathans@aussie.zone ⁨8⁩ ⁨months⁩ ago

      Is theta in radians? That’s the only way I see this working

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  • SkybreakerEngineer@lemmy.world ⁨8⁩ ⁨months⁩ ago

    Kepler’s Equation

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