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turkey pot pies

⁨172⁩ ⁨likes⁩

Submitted ⁨⁨1⁩ ⁨year⁩ ago⁩ by ⁨fossilesque@mander.xyz⁩ to ⁨science_memes@mander.xyz⁩

https://mander.xyz/pictrs/image/4f877d52-0f38-4ad7-a816-d242aa8ed51e.jpeg

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Comments

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  • brisk@aussie.zone ⁨1⁩ ⁨year⁩ ago

    This meme does meat pies dirty (unless “mincemeat pie” is one of those horribly deceptive terms like “mince pie”)

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    • paholg@lemm.ee ⁨1⁩ ⁨year⁩ ago

      A mincemeat pie is another name for a mince pie. So yeah.

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      • usualsuspect191@lemmy.ca ⁨1⁩ ⁨year⁩ ago

        Mincemeat is not the same, at least where I’m from… Mincemeat is dried fruit and spices, no meat

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      • brisk@aussie.zone ⁨1⁩ ⁨year⁩ ago

        Then I take it back. I have never been as disappointed as the first time I was offered a “mince” pie

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    • multifariace@lemmy.world ⁨1⁩ ⁨year⁩ ago

      The more savory a pie gets, the more I like it. Pumpkin pie is okay. Mince meat is fine. Turkey is great!

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      • FuglyDuck@lemmy.world ⁨1⁩ ⁨year⁩ ago

        Pumpkin pie is the devil.

        But there is something amazing about chicken/turkey pot pies or other savory pies in that vein.

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    • HeyMrDeadMan@lemmy.world ⁨1⁩ ⁨year⁩ ago

      French meat pie (Tourtiere) was always my favorite part of family Thanksgiving.

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  • southsamurai@sh.itjust.works ⁨1⁩ ⁨year⁩ ago

    They’ve never had a good mincemeat pie then.

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  • Wilzax@lemmy.world ⁨1⁩ ⁨year⁩ ago

    How can a probability be the null set?

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  • Leviathan@lemmy.world ⁨1⁩ ⁨year⁩ ago

    What’s going on here? Mincemeat pies are delicious.

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  • randomsnark@lemmy.ml ⁨1⁩ ⁨year⁩ ago

    missed opportunity to mention to volume of a pizza pie with radius z and depth a

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  • ryannathans@aussie.zone ⁨1⁩ ⁨year⁩ ago

    Theta minus sin theta? What does that give you

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    • TheOakTree@beehaw.org ⁨1⁩ ⁨year⁩ ago

      (1/2)×θ×r^2

      gives you the area of a sector circle, like a slice of pie.

      (1/2)×θ×side1×side2

      is the side-angle-side formula for the area of a triangle.

      We know that the triangle has two sides that are equal to the radius, so we replace side1×side2 with r^2. Since the area of the arc segment is equal to the area of a sector minus the triangle encompassed by the sector, we can subtract triangle area from sector area to get

      (1/2)×(θ-sin(θ))×r^2

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      • ryannathans@aussie.zone ⁨1⁩ ⁨year⁩ ago

        Is theta in radians? That’s the only way I see this working

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    • SkybreakerEngineer@lemmy.world ⁨1⁩ ⁨year⁩ ago

      Kepler’s Equation

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