Comment on This feels wrong. I love it.
jerkface@lemmy.ca 3 weeks ago
Doesn’t this also imply that i == 1 because CB is zero, forcing AC and AB to be coincident? That sounds like a disproving contradiction to me.
Comment on This feels wrong. I love it.
jerkface@lemmy.ca 3 weeks ago
Doesn’t this also imply that i == 1 because CB is zero, forcing AC and AB to be coincident? That sounds like a disproving contradiction to me.
xor@lemmy.blahaj.zone 3 weeks ago
I think BAC is supposed to be defined as a right-angle, so that AB²+AC²=CB²
=> AB+1²=0²
=> AB = √-1
=> AB = i
jerkface@lemmy.ca 3 weeks ago
I mean, I see that’s how they would have had to get to i, but it’s not a right triangle.
Knock_Knock_Lemmy_In@lemmy.world 3 weeks ago
i is at a right angle (pi/2) to 1 by definition.