Comment on How did gravity worked on the Death Star?

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Khrux@ttrpg.network ⁨3⁩ ⁨months⁩ ago

Yeah the fact it’s called a small moon is slightly deceptive to us because our moon is absolutely huge as far as moons go. The natives of the SW universe would be used to much much smaller moons.

For reference, our moon is 3475km across and the death star is 150km across, so it’s diameter is 23 smaller. It’s also weighed at about 900million tonnes or 9*10^14kg.

If I’m right (which I’m likely not). g=(GM)/r² or g=(6.66710^-119*10^13)/75².

That’s a gravity of 1.086x10^-5m/s² or if I round with pure disrespect for physics, 100,000 times weaker than earth’s gravity. Essentially it’s totally negligible compared to their artificial gravity. Hell, I don’t even think a marble on the floor would overcome it’s own grip and roll towards the center of the space station.

My maths is almost certainly wrong somewhere here, I failed it badly.

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