The exact dimensions of an 80-pound stainless steel block would depend on its specific shape. However, we can estimate its size based on the density of stainless steel, which is around 490 lbs per cubic foot (lb/ft³). To find the volume of the block, we can divide its weight (80 lbs) by its density (490 lb/ft³): Volume = Weight / Density Volume = 80 lbs / 490 lb/ft³ Volume ≈ 0.16 cubic feet (ft³) Since we don’t have a specific shape for the block, let’s assume it’s a cube for simplicity. To calculate the side length of a cube with a volume of 0.16 ft³, we can take the cube root of the volume: Side length = ³√Volume Side length = ³√0.16 ft³ Side length ≈ 0.54 ft (or about 6.5 inches) Therefore, an 80-pound stainless steel block shaped like a cube would have sides measuring around 6.5 inches each.