Comment on I just cited myself.

• ColeSloth@discuss.tchncs.de ⁨4⁩ ⁨months⁩ ago

  Except it doesn’t. The math is wrong. Do the exact same formula, but use .5555… instead of .9999…

  Guess it turns out .5555… is also 1.

  source

  • WldFyre@lemm.ee ⁨4⁩ ⁨months⁩ ago

    Lol you can’t do math apparently, take a logic course sometime

    Let x=0.555…

    10x=5.555…

    10x=5+x

    9x=5

    x=5/9=0.555…

    source
  • Reddfugee42@lemmy.world ⁨4⁩ ⁨months⁩ ago

    Oh honey

    source
  • pyre@lemmy.world ⁨4⁩ ⁨months⁩ ago

    you have to do this now

    source
• SmartmanApps@programming.dev ⁨4⁩ ⁨months⁩ ago

  you can prove it with math

  Not a proof, just wrong. In the “(substitute 0.9999… = x)” step, it was only done to one side, not both (the left side would’ve become 9.99999), therefore wrong.

  source

  • ytg@sopuli.xyz ⁨4⁩ ⁨months⁩ ago

    The substitution property of equality is a part of its definition; you can substitute anywhere.

    source

    • SmartmanApps@programming.dev ⁨4⁩ ⁨months⁩ ago

      you can substitute anywhere

      And if you are rearranging algebra you have to do the exact same thing on both sides, always

      source

      • SmartmanApps@programming.dev ⁨4⁩ ⁨months⁩ ago

        And if you don’t then you can no longer claim they are still equal.

        source

        • -> View More Comments
  • zarkanian@sh.itjust.works ⁨4⁩ ⁨months⁩ ago

    They multiplied both sides by 10.

    0.9999… times 10 is 9.9999…

    X times 10 is 10x.

    source

    • SmartmanApps@programming.dev ⁨4⁩ ⁨months⁩ ago

      X times 10 is 10x

      10x is 9.9999999…

      As I said, they didn’t substitute on both sides, only one, thus breaking the rules around rearranging algebra. Anything you do to one side you have to do to the other.

      source