Comment on I just cited myself.
myslsl@lemmy.world 10 months agoHe is right. 1 approximates 1 to any accuracy you like.
Comment on I just cited myself.
myslsl@lemmy.world 10 months agoHe is right. 1 approximates 1 to any accuracy you like.
pruwybn@discuss.tchncs.de 10 months ago
Is it true to say that two numbers that are equal are also approximately equal?
SpeakerToLampposts@lemmy.world 10 months ago
I recall an anecdote about a mathematician being asked to clarify precisely what he meant by “a close approximation to three”. After thinking for a moment, he replied “any real number other than three”.
mpa92643@lemmy.world 10 months ago
“Approximately equal” is just a superset of “equal” that also includes values “acceptably close” (using whatever definition you set for acceptable).
Unless you say something like:
a ≈ b ∧ a ≠ b
which implies a is close to b but not exactly equal to b, it’s safe to presume that a ≈ b includes the possibility that a = b.
EatATaco@lemm.ee 10 months ago
Can I get a citation on this? Because it doesn’t pass the sniff test for me. en.wikipedia.org/wiki/Approximation
mpa92643@lemmy.world 10 months ago
Sure! See ISO-80000-2
Here’s a link: cdn.standards.iteh.ai/…/ISO-80000-2-2019.pdf
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match@pawb.social 10 months ago
np.isClose(3, 3) is TRUE
myslsl@lemmy.world 10 months ago
Yes, informally in the sense that the error between the two numbers is “arbitrarily small”. Sometimes in introductory real analysis courses you see an exercise like: “prove if x, y are real numbers such that x=y, then for any real epsilon > 0 we have |x - y| < epsilon.” Which is a more rigorous way to say roughly the same thing. Going back to informality, if you give any required degree of accuracy (epsilon), then the error between x and y (which are the same number), is less than that required degree of accuracy
Leate_Wonceslace@lemmy.dbzer0.com 10 months ago
It depends on the convention that you use, but in my experience yes; for any equivalence relation, and any metric of “approximate” within the context of that relation, A=B implies A≈B.