I found out last doctor’s appointment my vitamin d is insanely low so I started taking a supplement this week and it’s made a world of difference already! Highly recommend trying it out if you feel burnt out and low energy all the time especially if you spend a lot of time inside. Its also relatively pretty cheap all things considered which is nice.
Vitamin D deficiency as well!
If your shadow is longer than you are tall, you are not getting enough ultraviolet radiation to produce vitamin D. You need about 15 minutes a day.
It is extremely common to be deficient in the northern part of North America, all of Canada, and the United Kingdom.
Some of the symptoms are fatigue and depression
BackpackCat@lemmy.world 6 months ago
Psych@lemmy.sdf.org 6 months ago
What is this shadow longer than your tall thing ? I have never heard of it lol . Can you explain how to check it or why it is a thing that happens and is real ?
kambusha@sh.itjust.works 6 months ago
I think that’s saying that if you go out at sunrise/sunset, the sun is on the horizon, and so your shadow will be a lot longer. In that scenario, you aren’t getting enough UV to produce the vitamin D you need.
Psych@lemmy.sdf.org 6 months ago
Still I don’t understand does shadows have something to do with vitamin D ?
Trail@lemmy.world 6 months ago
No. It means how high is the sun.
userflairoptional@lemmynsfw.com 6 months ago
A shallow angle from the sun give you that long shadow, but it also gives the light lots of extra air to pass through sideways on it’s way down out of space. The extra air filters out more light, and without an intense enough light your skin won’t make Vitamin D.
Fermion@feddit.nl 6 months ago
If you have a long shadow, the sunlight that gets to you has gone through much more atmosphere which attenuates the ultraviolet light. So at high/low lattitudes and during morning/evening hours the amount of uv that gets to the surface is much lower.
gravitas_deficiency@sh.itjust.works 6 months ago
Angle of the sun. Sunlight’s not intense enough for your skin to use the radiation to help generate the D.