We asume
π has an infinite amount of decimals.
RobotFK@lemmy.blahaj.zone 1 day ago
FishFace@piefed.social 1 day ago
Nope, the proof has been known since ancient times!
mkwt@lemmy.world 1 day ago
The proof is not that ancient. Pi was proven to be irrational in 1761, and proven to be transcendental in 1882.
For a long time the problem was known as “squaring the circle”: Given a circle in a plane, construct a square with the same area using a compass and straightedge. This was a famous unsolved problem in mathematics from antiquity all the way through the renaissance.
FishFace@piefed.social 1 day ago
Thanks for the correction - misremembered that.
A slight clarification in return: the constructible numbers are a strict subset of the algebraic (i.e. non-transcendental) real numbers.
(The constructible numbers are those numbers resulting from the closure of the rational numbers under square roots.)
This means that although the proof of pi’s transcendentality proved that squaring the circle is impossible, it could have been the case that pi was neither transcendental nor constructible. A simple example of such a number is the cube root of 2.
RobotFK@lemmy.blahaj.zone 20 hours ago
Thanks for the info :)
yetAnotherUser@discuss.tchncs.de 19 hours ago
So does every number:
6.000000…
Johandea@feddit.nu 16 hours ago
Or 5.999… It’s equal to 6 but it appears to have a much more impressive decimal expansion