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uh it should be in kgs sorry, I was just bewildered how I managed to fuck up an equation with it literally being in front of me (cus I googled it). The number comes up to a little less than 2 protons… which means (according to my food poisoned brain’s calculation) that if there were 2 protons in a sphere with a radius of 15 cm, it would collapse into a black hole.

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MajorasTerribleFate@lemmy.zip ⁨2⁩ ⁨days⁩ ago
So you’re saying that 2 protons closer than 15 cm would collapse into a black hole? That’s got me pretty worried, because I have a lot more than 2 protons within that proximity in my body, by at least an order of magnitude or so

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- Dave2@lemmy.blahaj.zone ⁨2⁩ ⁨days⁩ ago
  yeah sorry, its all blackholes now
  
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betanumerus@lemmy.ca ⁨2⁩ ⁨days⁩ ago
Well anyway, that’s wrong too. Density makes a black hole, not just weight. And you’re on the wrong extreme of density.

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- Dave2@lemmy.blahaj.zone ⁨2⁩ ⁨days⁩ ago
  is density not just weight divided by volume? I had a set volume (assumed the cat was a sphere with a radius of 15 cm), where am I wrong…
  
  And yes the calculation is wrong, that was the point, I WAS TRYING TO BE FUNNY.
  
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  - betanumerus@lemmy.ca ⁨2⁩ ⁨days⁩ ago
    I know this is only for fun, but what you have to do is: fix cat weight and calculate cat radius (instead of fixing cat radius and calculating cat weight). 🙂
    
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    Dave2@lemmy.blahaj.zone ⁨1⁩ ⁨day⁩ ago
    Alright mate, you and I seem to be having a major problem with communication. I am not trying to see how much I would have to squeeze a normal cat to form a blackhole, I am trying to see how much a cat would have to weigh to form a blackhole as it curled up. And an equation can be used to find any component of said equation as long it is the only one missing, so there is no one thing I “have to do”. I am really feeling like you’re disrespecting me here.
    
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