Comment on That explains a lot

• sp3tr4l@lemmy.zip ⁨4⁩ ⁨days⁩ ago

  vttoth.com/…/311-hawking-radiation-calculator

  Indeed, any black hole with a mass greater than about 0.75% of the Earth’s mass is colder than the cosmic background, and thus its mass increases for now. As the universe expands and cools, however, eventually the black hole may begin to lose mass-energy through Hawking radiation.

  Size isn’t the main factor, mass is.

  A teaspoon of what neutron stars are made of weighs as much as Mt. Everest.

  Its the mass, and apparently the threshold for an actually stable black hole is 0.75% the mass of Earth, 4.48 x 10²² kg … or, roughly 2/3 the mass of the Moon.

  So… basically 0 chance in our natural life times we’ll figure out how to convert the Moon into a blackhole, lol.

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  • Revan343@lemmy.ca ⁨4⁩ ⁨days⁩ ago

    We’re fucked if a black hole hits us, but we’re fucked if anything with the same mass hits us

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  • Maggoty@lemmy.world ⁨4⁩ ⁨days⁩ ago

    That is fascinating. Thank you.

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• ILikeBoobies@lemmy.ca ⁨4⁩ ⁨days⁩ ago

  If you do, you may win a Nobel prize for it

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• DogWater@lemmy.world ⁨4⁩ ⁨days⁩ ago

  I know a little bit but I’m not an expert.

  My understanding is hawking radiation will produce a rate of mass evaporating that’s fairly consistent over galactic time scales, so you just need to make sure the black hole is big enough to “suck” more mass in via gravitational attraction per given time period than evaporates through hawking radiation.

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  • interdimensionalmeme@lemmy.ml ⁨4⁩ ⁨days⁩ ago

    I think the bigger they are faster tge evaporate. They lose mass at some ratio between their surface and mass.

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    • WiseThat@lemmy.ca ⁨4⁩ ⁨days⁩ ago

      Exactly the opposite. The bigger one is, the less it evaporates. Time required to evaporate scales with Mass^3

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    • DogWater@lemmy.world ⁨4⁩ ⁨days⁩ ago

      That’s true the constant rate I mentioned would vary with the surface area of the black hole as it changes but the volume would increase exponentially faster

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