Comment on The grand prize

• Jiggle_Physics@lemmy.world ⁨1⁩ ⁨month⁩ ago

  I mean, I can only estimate it’s size from the person standing next to it. From there I can use that estimate to get the volume of the cube, then the weight, then look up the cost by weight right now and apply the average.

  So it would be somewhere around 1mm by weight.

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• Alwaysnownevernotme@lemmy.world ⁨1⁩ ⁨month⁩ ago

  By weight probably, for it to be a perfectly symmetrical cube would likely cost you double that.

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