By weight probably, for it to be a perfectly symmetrical cube would likely cost you double that.
Comment on The grand prize
weker01@sh.itjust.works 3 weeks agoThat is surprisingly little. Are you sure?
Alwaysnownevernotme@lemmy.world 3 weeks ago
Jiggle_Physics@lemmy.world 3 weeks ago
I mean, I can only estimate it’s size from the person standing next to it. From there I can use that estimate to get the volume of the cube, then the weight, then look up the cost by weight right now and apply the average.
So it would be somewhere around 1mm by weight.