Comment on Rip lol

• glorkon@lemmy.world ⁨1⁩ ⁨month⁩ ago

  Let’s do it:

  The phenomenon that causes divers to be trapped is called differential pressure, or Delta P. It requires surprisingly little Delta P to trap divers in such a way that they can’t free themselves.

  The formula is simple: F=Δp⋅A Δp = Differential pressure, A = the area the differential pressure acts on, in our case the cross sectional area of the pipe.

  #Example

  30 cm pipe => A = π⋅(0,15)² Delta P only (!!!) 0.1 bar (= 10 kPa).

  F = 10,000 Pa ⋅ 0.07 m² ≈ 700 N. This equals roughly 71.38 kg of weight.

  #Now, let’s try this with the numbers above. Unfortunately, we don’t know the diameter of the pipe so let’s again assume 30 cm.

  Δp = 21.375 - 14.7 psi = 6.675 psi ≈ 0.46 bar = 46 kPA

  F = 46,000 Pa ⋅ 0.07 m² ≈ 3250 N. So you would be sucked to this pipe opening with a force of roughly 330 kg.

  #For fun, let’s assume a 50 cm diameter pipe:

  F = 46,000 Pa ⋅ 0.196 m² ≈ 9020 N. This equals roughly 920 kg of pressure.

  There is absolutely no escape here and I think it’s safe to assume the diver would be sucked through that pipe.

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  • prenatal_confusion@feddit.org ⁨1⁩ ⁨month⁩ ago

    Ah, I didn’t make myself clear. I am and was absolutely convinced that you can’t free yourself once “plugged” unless very lucky. I was thinking about the bring sucked into pieces aspect. But it’s the same calculation I guess. How much force can human body structure take? I think 330kg static pressure wouldn’t rip you apart but when there is some movement involved there is some extra momentum. I think that could work. Or we increase the area. But then we don’t have the nice space movie effect of being sucked through a small slot.

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