Do you mean “c” instead of “g”? I don’t think there are a lot of “g” in interplanetary travel.
Comment on HD 137010 b
josephc@lemmy.ml 2 days ago
If we could accelerate at a constant 1g, flip, and decelerate at a constant 1g, the trip would take ~152 years… from Earth’s perspective. If you were onboard, time dilation would make the trip about 10 years.
zod000@lemmy.dbzer0.com 1 day ago
josephc@lemmy.ml 1 day ago
I mean ‘g’. 1g is 9.81m/s^2. c is a speed, not an acceleration. g is acceleration.
Not coincidentally, it’s the acceleration you experience from Earth’s gravity, but it doesn’t have to come from gravity. Astronauts routinely experience 3gs during takeoff from their rocket boosters.
If you were in a rocket that accelerated at a constant 1g it would feel like Earth’s gravity, even in space.
zod000@lemmy.dbzer0.com 1 day ago
I understand now, thanks.
Siethron@lemmy.world 1 day ago
No, g is a measure of acceleration equal to Earth’s gravitational pull at the surface of earth (approx 9.8 meters per second per second). ‘c’ is the speed of light, you can’t accelerate with a speed.
zod000@lemmy.dbzer0.com 1 day ago
Ok, thanks for the clarification, I clearly misunderstood “g” and how it was used.
altphoto@lemmy.today 2 days ago
1g! We have like 6g now!
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