Comment on I dunno
moriquende@lemmy.world 2 days agoBut factorised terms are multiplications, so they’re still following the same rules: a(b+c) = a*(b+c)
Example: 2(3+5)=16, and also 23+25=16
Comment on I dunno
moriquende@lemmy.world 2 days agoBut factorised terms are multiplications, so they’re still following the same rules: a(b+c) = a*(b+c)
Example: 2(3+5)=16, and also 23+25=16
SmartmanApps@programming.dev 2 days ago
No, they’re Distribution done in the Brackets step, a(b+c)=(ab+ac), now solve (ab+ac)
Nope! a(b+c)=(ab+ac). 1/a(b+c)=1/(ab+ac), but 1/ax(b+c)=(b+c)/a.
(23+25) actually, or you’ll get the wrong answer when it follows a Division sign. See previous point
moriquende@lemmy.world 2 days ago
Nope, that’s wrong. See www.wolframalpha.com/input?i=10%2F2(2%2B3) for reference.
SmartmanApps@programming.dev 2 days ago
You think Maths textbooks are wrong?? 😂
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See Maths textbooks for reference 😂
moriquende@lemmy.world 2 days ago
Yes, the math textbook says exactly what I said, that it’s a multiplication. There’s no mention of it being a separate operation taking precedence. The parentheses in your example are added for clarity.