Comment on I dunno

• moriquende@lemmy.world ⁨2⁩ ⁨days⁩ ago

  But factorised terms are multiplications, so they’re still following the same rules: a(b+c) = a*(b+c)

  Example: 2(3+5)=16, and also 23+25=16

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  • SmartmanApps@programming.dev ⁨2⁩ ⁨days⁩ ago

    But factorised terms are multiplications,

    No, they’re Distribution done in the Brackets step, a(b+c)=(ab+ac), now solve (ab+ac)

    a(b+c) = a*(b+c)

    Nope! a(b+c)=(ab+ac). 1/a(b+c)=1/(ab+ac), but 1/ax(b+c)=(b+c)/a.

    23+25=16

    (23+25) actually, or you’ll get the wrong answer when it follows a Division sign. See previous point

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    • moriquende@lemmy.world ⁨2⁩ ⁨days⁩ ago

      1/a(b+c)=1/(ab+ac)

      Nope, that’s wrong. See www.wolframalpha.com/input?i=10%2F2(2%2B3) for reference.

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      • SmartmanApps@programming.dev ⁨2⁩ ⁨days⁩ ago

        Nope, that’s wrong

        You think Maths textbooks are wrong?? 😂

        Image

        Image

        See www.wolframalpha.com/input?i=10%2F2(2%2B3) for reference

        See Maths textbooks for reference 😂

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