Comment on I dunno

• SmartmanApps@programming.dev ⁨1⁩ ⁨day⁩ ago

  Wouldn’t we just assume function expressions are always “in parenthesis”?

  No, because factorised Terms also are, ab+ac=a(b+c).

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  • moriquende@lemmy.world ⁨1⁩ ⁨day⁩ ago

    But factorised terms are multiplications, so they’re still following the same rules: a(b+c) = a*(b+c)

    Example: 2(3+5)=16, and also 23+25=16

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    • SmartmanApps@programming.dev ⁨1⁩ ⁨day⁩ ago

      But factorised terms are multiplications,

      No, they’re Distribution done in the Brackets step, a(b+c)=(ab+ac), now solve (ab+ac)

      a(b+c) = a*(b+c)

      Nope! a(b+c)=(ab+ac). 1/a(b+c)=1/(ab+ac), but 1/ax(b+c)=(b+c)/a.

      23+25=16

      (23+25) actually, or you’ll get the wrong answer when it follows a Division sign. See previous point

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      • moriquende@lemmy.world ⁨1⁩ ⁨day⁩ ago

        1/a(b+c)=1/(ab+ac)

        Nope, that’s wrong. See www.wolframalpha.com/input?i=10%2F2(2%2B3) for reference.

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