Alright mate, you and I seem to be having a major problem with communication. I am not trying to see how much I would have to squeeze a normal cat to form a blackhole, I am trying to see how much a cat would have to weigh to form a blackhole as it curled up. And an equation can be used to find any component of said equation as long it is the only one missing, so there is no one thing I “have to do”. I am really feeling like you’re disrespecting me here.
I always thought that leaving a conversation unfinished was a rude thing. What I was trying to find (as I have previously said) is how much a cat would have to weigh to collapse into a blackhole (assuming the cat when curled up would resemble a sphere with a radius of 15 cm). Last thing, how is “a more common problem” any helpful? I appreciate you trying to help but it feels like telling somebody, who is drowning, that breathing air instead of water would prevent drowning. Again, thank you for trying to be helpful.
Dave2@lemmy.blahaj.zone 11 months ago
Alright mate, you and I seem to be having a major problem with communication. I am not trying to see how much I would have to squeeze a normal cat to form a blackhole, I am trying to see how much a cat would have to weigh to form a blackhole as it curled up. And an equation can be used to find any component of said equation as long it is the only one missing, so there is no one thing I “have to do”. I am really feeling like you’re disrespecting me here.
betanumerus@lemmy.ca 11 months ago
Dave2@lemmy.blahaj.zone 11 months ago
I always thought that leaving a conversation unfinished was a rude thing. What I was trying to find (as I have previously said) is how much a cat would have to weigh to collapse into a blackhole (assuming the cat when curled up would resemble a sphere with a radius of 15 cm). Last thing, how is “a more common problem” any helpful? I appreciate you trying to help but it feels like telling somebody, who is drowning, that breathing air instead of water would prevent drowning. Again, thank you for trying to be helpful.