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Comment on UwU brat mathematician behavior

marcos@lemmy.world ⁨1⁩ ⁨week⁩ ago

Hum… I don’t think the integral “operator” applies by multiplication.

You can put the dx at the beginning of the integral, but not before it.

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LeFrog@discuss.tchncs.de ⁨1⁩ ⁨week⁩ ago
Physicists be like: whitness me

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- marcos@lemmy.world ⁨1⁩ ⁨week⁩ ago
  Nobody on your link is treating the integral “operator” as multiplicative.
  
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OrganicMustard@lemmy.world ⁨1⁩ ⁨week⁩ ago
If you were using nonstandard analysis with dx an infinitesimal you could put it outside I guess. Maybe with differential forms too?

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- marcos@lemmy.world ⁨1⁩ ⁨week⁩ ago
  Switch it with a summation operator and see if it makes sense. The problem isn’t the operation by itself, but the fact that the operator implies an argument application, like a function.
  
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  - OrganicMustard@lemmy.world ⁨1⁩ ⁨week⁩ ago
    In the case of dx as an infinitesimal it makes sense. You are making a sum of all the values of the function in the integral range and multiplying with a constant dx.
    
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- kogasa@programming.dev ⁨1⁩ ⁨week⁩ ago
  In the context of differential forms, an integral expression isn’t complete without an integral symbol and a differential form to be integrated.
  
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