Comment on Listen here, Little Dicky
iAvicenna@lemmy.world 5 weeks ago
Look it is so simple, it just acts on an infinite dimensional vector space of differentiable functions.
Comment on Listen here, Little Dicky
iAvicenna@lemmy.world 5 weeks ago
Look it is so simple, it just acts on an infinite dimensional vector space of differentiable functions.
gandalf_der_12te@discuss.tchncs.de 5 weeks ago
fun fact: the vector space of differentiable functions (at least on a compact domain) is actually of countable dimension.
iAvicenna@lemmy.world 5 weeks ago
Doesn’t BCT imply that an infinite dimensional Banach spaces cannot have a countable basis
gandalf_der_12te@discuss.tchncs.de 5 weeks ago
Uhm, yeah, but there’s two different definitions of basis iirc. And i’m using the analytical definition here; you’re talking about the algebraic definition.
iAvicenna@lemmy.world 5 weeks ago
So I call an infinite dimensional vector space of countable/uncountable dimensions if it has a countable and uncountable basis. What is the analytical definition?