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A wonderful coincidence or an expected connection: why π² ≈ g

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Submitted ⁨⁨1⁩ ⁨year⁩ ago⁩ by ⁨bot@lemmy.smeargle.fans [bot]⁩ to ⁨hackernews@lemmy.smeargle.fans⁩

https://roitman.io/blog/91

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  • lvxferre@mander.xyz ⁨1⁩ ⁨year⁩ ago

    TL;DR: the old definition of the meter was based on the length of a string necessary to make a pendulum oscillate once each 2s. And since the oscillation of a pendulum depends on both gravity and π, by assigning that length the value of one unit, you end with gravity as π².

    This gets easier to see if you actually include the units into the equation:

    T = 2π√(l/g) // the formula for pendulum oscillation
    T² = 4π²l/g // getting rid of square roots, bloody roots
    g = 4π²l/T² // same junk as above, just reorganised
    g = 4π²l/(2s)² // pendulum oscillation arbitrarily chosen to be 2s
    g = π²l/s² // cancelling out 4 and 2²
    g = π²(1m)/s² // "we shall call that length ONE METRE!"
    g = π²m/s² // gravity is pi times pi, plus typical accel unit
    
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