Comment on So much
emergencyfood@sh.itjust.works 2 months ago
Not a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.
Comment on So much
emergencyfood@sh.itjust.works 2 months ago
Not a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.
davidagain@lemmy.world 2 months ago
You’re right on all three counts. It’s not always true, f(x0) has to be L, and the function has to be continuous.