Comment on Is there a house advantage in a "double-or-nothing" coin flip game?
ada@lemmy.blahaj.zone 3 months ago
Once the player loses, the chain ends, and the house wins. So as long as the house can afford to keep pushing the player in to trying again, they’re going to create more opportunities for the player to return their winnings to the house.
HandwovenConsensus@lemm.ee 3 months ago
Right, and as the chain continues, the probability of the player maintaining their streak becomes infinitesimal. But the potential payout scales at the same rate.
If the player goes for 3 rounds, they only have a 1/8 chance of winning… but they’ll get 8 times their initial bet. So it’s technically a fair game, right?
rowinxavier@lemmy.world 3 months ago
If everyone has the same amount of starting capital it is a fair game assuming both can opt out at any time.
That said, the house appears to not be able to opt out (they definitely can, you just don’t think about that part), and the house has more capital. For them each time someone plays a round there are only 3 possible outcomes. Half are the player loses, then a quarter are the player wins and plays another round, and lastly a quarter are the player wins and ends the game. The only case where the player wins is option 3, in all other cases, so 75%, the house wins because the next round has another chance to make the player lose directly at a 50/50 chance or play another round.
Hobbes@startrek.website 3 months ago
They have a 50/50 chance each round. Doesn’t matter how many rounds they’ve won.
HandwovenConsensus@lemm.ee 3 months ago
I’m looking at the game as a whole. The player has a 1 in 8 chance of winning 3 rounds overall.