nooneescapesthelaw@mander.xyz 3 days ago
Let’s first state our assumptions:
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Very thin membrane, the balloon skin cannot be compressed more than it already is
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Zero trapped air
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Isothermal conditions, water temperature at the bottom of the ocean is the same as the top, that way we don’t need to deal with thermal expansion
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Balloon is a perfect sphere
Calculations:
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Pressure on the balloon is densitygravitydepth ~= 100010100 = 1 Mpa or 10 atmospheres
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The bulk modulus of water is 2.2 Gpa so (change in volume)/(initial volume) = (change in pressure)/(bulk modulus) = 0.0046% decrease in volume
0.0046% decrease in volume is like a 0.015% decrease in radius
magnetichuman@fedia.io 3 days ago
is there a /m/theydidthemath ?
_NetNomad@fedia.io 2 days ago
/m/theydidthemonstermath