No.
You are wrong.
“Select the image that is unlike the other two.”
The only possible choice that results in a set of 2, and a set of 1, which are seperated cleanly by a distinct property, is picking C.
The goal is to define a difference between potential sets such that a distinct property exists between the two sets that you create.
To define two sets where unlikeness exists when they are compared.
Your job is not to merely compare three elements.
It is to compare three possible pairs of sets that can be made out of three elements.
fonix232@fedia.io 18 hours ago
And that's literally what they did.
There's a set of shapes that are filled, and a distinct set of one that is outline only.
There's a set of shapes that have 4 sides, and a distinct set of one that is 3 sides only.
There's a set of shapes that are red, and a distinct set of one shape that is green.
sp3ctr4l@lemmy.dbzer0.com 18 hours ago
Only when you pick C do you result in a pair of sets that are cleanly dvided by the same property difference.
Is that more clear?
If you pick C, the distinction between C and A is the same distinction between C and B.
Thus, if you pick C, C is unlike A and B in the same way.
This is what I would call a clean or clear distinction, or … kind of unlikeness.
This is not the case, does not occur, if you pick A or B.
You end up with a picked set of one element that differs from the remainder set in ways that are inconsistent among the elements of the remainder set.
IE, a muddled or inconsistent distinction.
fonix232@fedia.io 18 hours ago
No, you're still not correct just because you chose to reduce the similarities of C with A and B.
Again, I can make the same ignorant reduction of importance you did, but from a different aspect, and get a different answer.
The only reason you're picking C is psychological, as in, C is the most visually distinct due to the difference in colour (which is something human eyes are keyed towards). The rest of your explanation is a pseudointellectual attempt of forcing logic into your subjective choice, basically, you're Petersoning it real hard just to be right.
Just to make it clear, let's apply your same property difference.
If you pick A, the distinction between (A, B) and (A, C) is the same - they are filled, not outline.
If you pick B, the distinction between (B, A) and (B, C) is the same again - they have four sides, not 3.
So, again, the same property difference pair can be applied to literally any of the choices.
sp3ctr4l@lemmy.dbzer0.com 18 hours ago
Yep, you’re right.
KaChilde ran through a more thorough version of my own logic and I realized I am being a stubborn ass, sorry about that lol!
canofcam@lemmy.world 18 hours ago
I think you are overthinking this mate.
sp3ctr4l@lemmy.dbzer0.com 18 hours ago
I concur, and realized my logic is flawed.
… sorry.