If 5(4)^2^ is 5*16 then 2(8)^2^ is 2*64.
I get a free hoagie.
Comment on I dunno
SmartmanApps@programming.dev 3 days agoThis is a college textbook, and that explains how to solve it
It’s a college refresher course on high school Maths. They also forgot to cover The Distributive Law, which is not unusual given college Professors don’t actually teach high school Maths.
Another example
From the same refresher course 🙄
Alternatively, here is another example
Which also doesn’t cover The Distributive Law, which isn’t surprising given that chapter isn’t even about order of operations! 😂
In case you can’t find the correct part
Still not about a(b+c). You lot are investing so much effort into such an obvious False Equivalence argument it’s hilarious! 😂
mindbleach@sh.itjust.works 3 days ago
SmartmanApps@programming.dev 3 days ago
Don’t move the goalposts
I didn’t. You’re the one who has been desperately trying to make a False Equivalence argument between a(b+c) and a(bc)² 🙄
I’ve posted textbooks showing that “solving brackets” only applies to the inside,
No you haven’t. A college refresher isn’t a Maths textbook, and I already pointed out to you that they don’t mention The Distributive Law at all, unlike, you know, high school Maths textbooks 🙄
distribution is part of multiplication
And the high school Maths textbooks I posted prove you are wrong about that 🙄
and optional
And the high school Maths textbooks I posted prove you are wrong about that too, 🙄 unless you think “optional” is a valid interpretation of what “must” means 😂
You’ve said yourself your magic rule is taught in highschool,
Yep
so a refresher course in college would never ignore it
And yet you proved that they did in fact forget about it 🙄
Now instead of giving weak excuses
they say to person who has been backed up by every textbook they posted so far 😂
provide your part of the proof.
Just scroll back dude - they’re all still there, like here for example.
And I’m not talking about multiplication
Well that’ll be a nice change then 😂
I want to see anywhere where a distribution is given precedence over an exponent
Because you are hell bent on making a False Equivalence argument between a(b+c) and a(bc)². I don’t care dude. there is no exponent in the meme. I’ll take that as an admission that you are wrong about a(b+c) then.
mindbleach@sh.itjust.works 3 days ago
Who are you talking to?
All I said was: If 5(4)^2^ is 516, like this college math textbook shows, then 2(8)^2^ is 264.
Every published example will agree this is how it works. None, at any level of education, will agree with your bullshit.
moriquende@lemmy.world 3 days ago
Don’t move the goalposts. I’ve posted textbooks showing that “solving brackets” only applies to the inside, and distribution is part of multiplication and optional.
You’ve said yourself your magic rule is taught in highschool, so a refresher course in college would never ignore it.
Now instead of giving weak excuses, provide your part of the proof. And I’m not talking about multiplication, I want to see anywhere where a distribution is given precedence over an exponent.