Comment on I dunno
moriquende@lemmy.world 3 weeks agoUnsolved brackets
Solving brackets does not include forced distribution. Juxtaposition means multiplication, and as such, 2(3+5)² is the same as 2*(3+5)², so once the brackets result in 8, they’re solved.
Distribution needs to happen if you want to remove the brackets while there are still multiple terms inside, but it’s still a part of the multiplication. You can’t do it if there is an exponent, which has higher priority.
Your whole argument hangs on the misinterpretation of textbooks. This is what it feels like to argue against Bible fanatics lmao.
Tell you what, provide me a solver that says 2(3+5)² is 256 and you’ve won, it’s so easy no?
SmartmanApps@programming.dev 3 weeks ago
Yes it does! 😂
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No, a Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms…
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No it isn’t. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms
They don’t - you still have an undistributed coefficient, 2(8)
Not until you’ve Distributed and Simplified they aren’t
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if you want to remove the brackets, YES, that’s what the Brackets step is for, duh! 😂
As in 2(8)=(2x8) is multiple Terms inside 😂
Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed
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It doesn’t have a higher priority than Brackets! 🤣
says person who can’t cite any textbooks that agree with them, wrongly calls Products “Multiplication”, and claimed that I invented a rule that is in an 1898 textbook! 🤣
says the Bible fanatic, who in this case can’t even show me what it says in The Bible (Maths textbooks) that agrees with them 😂
provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣
And in the meantime, here’s one saying it’s 1, because x(x-1) is a single Term…
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moriquende@lemmy.world 3 weeks ago
youtu.be/xoZzHMoB5qA
This is a college textbook, and that explains how to solve it.
Another example: stemjock.com/STEM Books/…/OSCACh1s1e32.pdf
Alternatively, here is another example: kingphilip.org/…/Supplemental_Topics_from_Algebra…
In case you can’t find the correct part: Image
SmartmanApps@programming.dev 3 weeks ago
It’s a college refresher course on high school Maths. They also forgot to cover The Distributive Law, which is not unusual given college Professors don’t actually teach high school Maths.
From the same refresher course 🙄
Which also doesn’t cover The Distributive Law, which isn’t surprising given that chapter isn’t even about order of operations! 😂
Still not about a(b+c). You lot are investing so much effort into such an obvious False Equivalence argument it’s hilarious! 😂
moriquende@lemmy.world 3 weeks ago
Don’t move the goalposts. I’ve posted textbooks showing that “solving brackets” only applies to the inside, and distribution is part of multiplication and optional.
You’ve said yourself your magic rule is taught in highschool, so a refresher course in college would never ignore it.
Now instead of giving weak excuses, provide your part of the proof. And I’m not talking about multiplication, I want to see anywhere where a distribution is given precedence over an exponent.
mindbleach@sh.itjust.works 3 weeks ago
If 5(4)^2^ is 5*16 then 2(8)^2^ is 2*64.
I get a free hoagie.