Comment on I dunno
SmartmanApps@programming.dev 1 day agoDude you’re not even hitting the right reply buttons anymore
Yes I am
Is that what you do when you’re drunk?
Is that why you think I’m hitting the wrong buttons?
It’d explain leading with ‘nope! I’ve said exactly what you accused me of.’
I have no idea what you’re talking about. Maybe stop drinking
You keep pretending distribution is different from multiplication
No pretending - is is different - it’s why you get different answers to 8/2(1+3) (Distribution) and 8/2x(1+3) (Multiplication) 😂
That’s not Multiplication, it’s Distribution, a(b+c)=(ab+ac), a(b)=(axb).
That’s right.
And then posting images that explicitly say the contents of the brackets should be multiplied
The “contents OF THE BRACKETS”, done in the BRACKETS step , not the MULTIPLICATION step - there you go quoting proof that I’m correct! 😂
Or that they can be simplified first.
That’s right, you can simplify then DISTRIBUTE, both part of the BRACKETS step, and your point is?
I am not playing dueling-sources with you
No, because you haven’t got any 😂
your own sources call bullshit on what you keep hassling strangers about
says person failing to give a single example of that EVER happenning 😂
I’ll take that as an admission of being wrong then. Thanks for playing
mindbleach@sh.itjust.works 1 day ago
Image
This is your own source - and it says, juxtaposition is just multiplication. It doesn’t mean E=mc^2^ is E=(mc)^2^.
Throwing other numbers on there is like arguing 1+2 is different from 2+1 because 8/1+2 is different from 8/2+1.
SmartmanApps@programming.dev 23 hours ago
inside brackets. Don’t leave out the inside brackets that they have specifically said you must use - “Parentheses must be introduced”! 🤣 BTW, this is a 19th Century textbook, from before they started calling them PRODUCTS 🙄
No, it means E=mc² is E=mcc=(mxcxc)
I have no idea what you’re talking about 🙄
mindbleach@sh.itjust.works 21 hours ago
But you understand E=mc^2^ does not mean E=(mxc)^2^.
This is you acknowledging that distribution and juxtaposition are only multiplication - and only precede other multiplication.
In your chosen Introduction To Algebra, Chrystal 1817, on page 80 (page 100 of the PDF you used), under Exercises XII, question 24 reads (x+1)(x-1)+2(x+2)(x+3)=3(x+1)^2^. The answer on page 433 of the PDF reads -2. If 3(x+1)^2^ worked the way you pretend it does, that would mean 3=9.
SmartmanApps@programming.dev 13 hours ago
I already answered, and I have no idea what your point is.
Nope. It’s me acknowledging they are both BRACKETS 🙄
E=mcc=(mxcxc) <== BRACKETS
a(b+c)=(ab+ac) <== BRACKETS
everything 😂