Comment on I dunno

• SmartmanApps@programming.dev ⁨1⁩ ⁨day⁩ ago

  Dude you’re not even hitting the right reply buttons anymore

  Yes I am

  Is that what you do when you’re drunk?

  Is that why you think I’m hitting the wrong buttons?

  It’d explain leading with ‘nope! I’ve said exactly what you accused me of.’

  I have no idea what you’re talking about. Maybe stop drinking

  You keep pretending distribution is different from multiplication

  No pretending - is is different - it’s why you get different answers to 8/2(1+3) (Distribution) and 8/2x(1+3) (Multiplication) 😂

  That’s not Multiplication, it’s Distribution, a(b+c)=(ab+ac), a(b)=(axb).

  That’s right.

  And then posting images that explicitly say the contents of the brackets should be multiplied

  The “contents OF THE BRACKETS”, done in the BRACKETS step , not the MULTIPLICATION step - there you go quoting proof that I’m correct! 😂

  Image

  Or that they can be simplified first.

  That’s right, you can simplify then DISTRIBUTE, both part of the BRACKETS step, and your point is?

  I am not playing dueling-sources with you

  No, because you haven’t got any 😂

  your own sources call bullshit on what you keep hassling strangers about

  says person failing to give a single example of that EVER happenning 😂

  I’ll take that as an admission of being wrong then. Thanks for playing

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  • mindbleach@sh.itjust.works ⁨1⁩ ⁨day⁩ ago

    Image

    This is your own source - and it says, juxtaposition is just multiplication. It doesn’t mean E=mc^2^ is E=(mc)^2^.

    Throwing other numbers on there is like arguing 1+2 is different from 2+1 because 8/1+2 is different from 8/2+1.

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    • SmartmanApps@programming.dev ⁨1⁩ ⁨day⁩ ago

      This is your own source - and it says, juxtaposition is just multiplication

      inside brackets. Don’t leave out the inside brackets that they have specifically said you must use - “Parentheses must be introduced”! 🤣 BTW, this is a 19th Century textbook, from before they started calling them PRODUCTS 🙄

      E=mc2 is E=(mc)2

      No, it means E=mc² is E=mcc=(mxcxc)

      Throwing other numbers on there

      I have no idea what you’re talking about 🙄

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      • mindbleach@sh.itjust.works ⁨23⁩ ⁨hours⁩ ago

        Because BRACKETS - ab=(axb) BY DEFINITION

        “Parentheses must be introduced”!

        But you understand E=mc^2^ does not mean E=(mxc)^2^.

        This is you acknowledging that distribution and juxtaposition are only multiplication - and only precede other multiplication.

        In your chosen Introduction To Algebra, Chrystal 1817, on page 80 (page 100 of the PDF you used), under Exercises XII, question 24 reads (x+1)(x-1)+2(x+2)(x+3)=3(x+1)^2^. The answer on page 433 of the PDF reads -2. If 3(x+1)^2^ worked the way you pretend it does, that would mean 3=9.

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