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The result is 𝑦 = ⅟ₓ, right?
No e^x doesn’t have a ‘y’ and so it also acts as a constant.
Oh, I was thinking of it as 𝑦 = 𝑒^𝑥^ or 𝑥 = ln 𝑦, whose derivative in respect to 𝑦 is 𝑥 = 1/𝑦 (for 𝑥 > 0) or 𝑦 = 1/𝑥 (for 𝑦 > 0).
yayaya, or in other cases like multiple independent variables, I’m not sure because it’s been 6 years since I took calculus
Papergeist@lemmy.world 18 hours ago
No e^x doesn’t have a ‘y’ and so it also acts as a constant.
ChaoticNeutralCzech@feddit.org 18 hours ago
Oh, I was thinking of it as 𝑦 = 𝑒^𝑥^ or 𝑥 = ln 𝑦, whose derivative in respect to 𝑦 is 𝑥 = 1/𝑦 (for 𝑥 > 0) or 𝑦 = 1/𝑥 (for 𝑦 > 0).
anothercatgirl@lemmy.blahaj.zone 6 hours ago
yayaya, or in other cases like multiple independent variables, I’m not sure because it’s been 6 years since I took calculus