Comment on Anon takes up microdosing
hobovision@lemm.ee 2 days ago“His way of thinking wouldn’t work because if he skipped a bunch of steps in his process, it would blow off his leg” isn’t the great argument you think it is.
Comment on Anon takes up microdosing
hobovision@lemm.ee 2 days ago“His way of thinking wouldn’t work because if he skipped a bunch of steps in his process, it would blow off his leg” isn’t the great argument you think it is.
sp3ctr4l@lemmy.dbzer0.com 2 days ago
Ok, yep, you can’t read.
At no point did I attempt to make an argument going into why his way of thinking is fundamentally flawed.
I simply gave an example of what would happen if he had continued on his given path.
I’m sorry, but do you require an anatomy/biology/physics lesson as the only acceptable way to clown on an idiotic 4chan post?
Why do you insist on interpreting what I said as an ‘argument’, as if it … isn’t common fucking knowledge that shooting yourself with a gun is an extremely stupid idea?
… Are you the OP from this 4chan post?
Do you need to have it broken down, step by step, why shooting yourself with a gun, is going to permanently injure you, likely quite severely?
That there is no evidence to support the idea that shooting yourself with progressively higher caliber/grain coint cartridges is not going to result in you gaining some kind of resistance to bullets?
hobovision@lemm.ee 2 days ago
No, I mean the guy in the post demonstrates it pretty clearly. Going from 22 pellets to 22 short was basically going from “this won’t maim you” to “this could kill you at close range”. Could he have used something else between those energies to further develop a callous tough enough to stop a 22 short? Ehh probably not, but going on about how a 223 will blow off his leg isn’t a good argument for why this method won’t work. It’s either a strawman or a non sequitor depending how you present it.
It’s like you’re making this argument: Paper will never stop a 223 bullet and here’s why. 10 layers stopped a small pellet sure, and 50 layers stopped a 22 pellet. But if you just make it 100 layers and shoot it with a 223 then it will explode because a 223 is at least 100 times more powerful and that’s only double the paper! No amount of paper could stop a 223.
sp3ctr4l@lemmy.dbzer0.com 1 day ago
Ok, you are apparently just a moron.
Again… the dude in the original post states that psrt of his original plan was to work his way up to a .223.
If you missed that part of the original image, please go look at and read it again.
Here, let me highlight it for you, as you struggle with reading comprehension:
Image
I have no idea why you keep insisting I am making some kind of strawman or non sequitor argument by just explaining what would happen if he just went to carrying out that part of his plan.
…
A .22 pellet air gun round carries about 5 to 15 ft-lbs of energy leaving the barrel.
A .22 short bullet from a firearm carries about 80 +/- 30 ft-lbs of energy leaving the barrel, though this will vary by the exact round and barrel length.
A .22 lr bullet carries 130 to 200 ft-lbs of energy, though this will vary by the exact round and barrel length.
A .223 bullet carries about 950 to 1350 ft-lbs of energy though this will vary by the exact round and barrel length.
…
Human skin, on the other hand, just has a hard limit of how many psi it can resist before breaking, about 100.
A callous may add maybe up to 10 to that number, but this is negligible with any firearm cartridge at point blank range.
Because all calibers mentioned in the OP image are either the same or very close to each other, the ft-lbs of energy is being applied to human skin/flesh over a very close to the same amount of surface area, so you don’t really need to take into account the potentially variable surface area to get a psi figure, and can instead just use ft-lbs as a decently accurate comparative measure of destructiveness.
The .22 refers to the diameter of the pellet/round, in inches, plug that in with the area of a circle formula (A = pi * (d/2)^2) and with a bit of rounding for simplicity, you get about 0.038 square inches.
Because this idiot is shooting himself point blank, the projectile travel distance is negligible, so you end up with Energy of Projectile / Area of Impact.
Because I am doing this in Imperial instead of Metric, lets just say all these .22 projectiles are roughly .22 in^3 volume… now you can do:
(ft-lbs of projectile energy / 12) / 0.038 in^3
~= impact psi
Because the two other numbers here are constant and do not change for everything from a .22 pellet up to a .223 cartridge… we can just say that:
ft-lbs * 2.2 ~= psi.
As you can see, the max of 15 ft-lbs from a pellet turns into 33 psi, under the skin breakage threshold.
Every single bullet the OP mentions, on the other hand, exceeds to vastly exceeds the max skin breakage threshold of 110 psi…
.22 short is about 180 psi
.22 lr is about 350 psi
.223 is about 2600 psi
… This is all middle school physics and math, apparently you either haven’t yet taken those classes or did not do well in them.
…
All of these rounds, and the pellet, are capable of being stopped by a certain number of sheets of paper, at certain ranges.
Even at literally 0 distance from the barrel of a gun, if you put enough phone books in front of an AR15 and fire a round, a certain number of phone books will stop a .223 round.
You can easily see this yourself without even leaving your seat:
There are many videos of such tests on youtube, ‘how many X will it take to stop Y cartridge?’ is a fairly popular video format… phone books often feature in such videos, as they are relatively cheap.
hobovision@lemm.ee 1 day ago
Sorry bud, it sounds like you think I believe someone could train their body to become bullet proof. That’s not what I’m saying.
I’m saying your argument is fallacious. Your conclusion is correct, but your argument fails.
Also, you can’t just convert impact energy to pressure like that. I’m not familiar with the equation you’re using (is it just energy divided by the volume of a 0.22" sphere?), but I do know that impact is much more complex than that. It’s going to depend on both the bullet and the impact surface. Bullet geometry and material will change things, for example hollow points vs full metal jacket. Then there’s the impact surface, it’s hardness, strength, ductility, even viscoplasticity (materials can deform in different ways at the really high strain rates you get in an impact event). Think about the way Kevlar armor works. It dissapates some of the energy by stretching and breaking the strands of Kevlar and it reduces the impact force on a body by spreading it over a larger area and slowing the bullet over a longer distance. The person wearing the Kevlar armor still gets much of that energy delivered to their body.