MinekPo1
@MinekPo1@lemmy.ml
- Comment on Let π = 5 6 months ago:
oopsie :3
- Comment on Let π = 5 6 months ago:
my mistake was using the sum of angles in a triangle which was kinda dum but whatever . I also tried calculating via the circumstance of a circle placed at a pole where π was 20x smaller for the case I was using but its not linear so I looked deeper which was a big mistake .
BTW the ratio of circumstance to radius for a circle which is also an equator of the space is ¼ not 1 (r=½π₀ , C=2π₀) .
- Comment on Let π = 5 6 months ago:
Better question: What curvature of space is necessary for the apparent value of π to be 5?
honestly I don’t know if there is any way to measure curvature of space , but its slightly more curved than the surface of a ball (where π=~4.712)
- Comment on Let π = 5 6 months ago:
minor nitpick but the value of π is technically a parameter of the space you are operating in . which means it can have any arbitrary value as long as you are willing to operate in non euclidean spaces (and the space we live in is not euclidean though not to a measurable extent unless you are near a black hole)
but yeah in this context saying π is a constant is as correct as saying you cant take a square root out of a negative number .