Comment on Is there a house advantage in a "double-or-nothing" coin flip game?

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HandwovenConsensus@lemm.ee ⁨2⁩ ⁨months⁩ ago

But the odds of the player managing to do so are proportionate. In theory, if 8 players each decide to go for three rounds, one of them will win, but the losings from the other 7 will pay for that player’s winnings.

You’re right that the house is performing a Martingale strategy. That’s a good insight. That may actually be the source of the house advantage. The scenario is ideal for a Martingale strategy to work.

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