Welp.
I tap out, you’re right lol.
Don’t attempt set theory before breakfast, otherwise you end up making a fool of yourself as I have.
=[
… only one choice is a triangle.
How is this difficult, other than if you are shape blind?
The correct choice is B.
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick B, while B does have elements in common with A and C…
(it shares ‘red’ with A, and ‘solid color fill’ with C)
… it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
B is the only choice where ‘is unlike the other two’… is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
sp3ctr4l@lemmy.dbzer0.com 16 hours ago
KaChilde@sh.itjust.works 16 hours ago
What a fool you are!
… only one choice is an outline.
How is this difficult, other than if you are line blind?
The correct choice is A.
If you pick B, A is also red, and C is also a filled solid. So B is not unlike either A or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick A, while A does have elements in common with B and C…
(it shares ‘red’ with B, and ‘4-gon’ with C)
… it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
A is the only choice where ‘is unlike the other two’… is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.