Comment on I dunno
mindbleach@sh.itjust.works 3 days agoSo you’re saying there no such rule as 2(ab)²=2a²b².
That would mean 2(8*1)^2^ is 128. You are the one saying it’s not 2a^2^b^2^, because you think it’s 2^2^a^2^b^2^, and that 2(8*1)^2^ is 256. I’m not touching anything without exponents because exponents are where you are blatantly full of shit.
if it has been written as 2(ab)², not if it has been written a(b+c)²
Source: your ass. Every published example disagrees, and you just go, nuh-uh, that up-to-date Maths textbook must be wrong. You alone are correct on this accursed Earth.
Hey look, another one of the textbooks you insist I read says you’re completely wrong: “The multiplication sign is often not included between letters, e.g. 3ab means 3 * a * b.” Page 31 of the PDF… right above where you’ve dishonestly twisted the “expanding brackets” text. Next page: “3(x+y) means 3*(x+y).”
Page 129 of that PDF, exercise 5, question 14: simplify 2(e^4^)^2^. The answer on PDF page 414 is 2e^8^. Your bullshit would say 4e^8^.
Right below that, exercise 5*, question 4: 4(4^4^)^4^. The answer on PDF page 414 is 1.72x10^10^. The bullshit you’ve made up would be 1.10x10^11^. 5* questions 7, 9, 10, and 11 also have the same a(b)^c^ format as 2(8)^2^, if you somehow need further proof of how this actually works.
PDF page 134, exam practice question 10a, simplify 3(q^2^)^2^. PDF page 415 says 3q^6^. Your bullshit says 9q^6^.
Damn dude, that’s five textbooks you chose saying you’re full of shit, and zero backing you up. One more and I get a free hoagie. Your bullshit has brought us to max comment depth.
SmartmanApps@programming.dev 3 days ago
Firstly, it’s hilarious that you’ve gone back to a previous comment, thus ignoring the dozen textbook references I posted 😂
That’s right, because we don’t Distribute over Multiplication (and Division), only Addition and Subtraction (it’s right there in the Property’s name - The Distributive Property of Multiplication over Addition). Welcome to you proving why a(bc)² is a special case 😂 I’ve been telling you this whole time that a(b+c) and a(bc) aren’t the same, and you finally stumbled on why they aren’t the same 😂
No I’m not. I never said that, liar. I’ve been telling you the whole time that it is a special case 🙄 (upon which you claimed there was no special case)
No I don’t. That’s why you can’t quote me ever saying that 🙄
and there are no exponents in a(b+c) and all this stuff about exponents is you being blatantly full of shit 🙄
No, this meme
Image
Notice that there are no exponents? 😂
says person who came back to this post to avoid this post which is full of published examples that agree with me - weird that 😂
And I also pointed out why that was wrong here. i.e. the post that you have avoided replying to 😂
No, all textbooks as well, except those which are using the old-fashioned and wrong syntax of (a+b)c, not to mention most calculators as well (only Texas Instruments is still doing it wrongly).
Before the pages I already posted in the post that you are avoiding replying to 😂
means not equals, Mr. Person Who Is Actually Dishonestly Twisting The Words, as proven by the exercises on Page 282, answers on Page 577, which are also in the post that you are avoiding replying to 😂
That’s right
Nope. Been telling you the whole time that is a special case, upon which you claimed there was no such special case 😂
No, I don’t, it’s still a False Equivalence argument 🙄 But if you wanna waste your time on an irrelevant point (which you seem determined to do), go ahead, don’t let me stop you, but that’s an admission that you are wrong about a(b+c)
Nope! None of them have said a(b+c)=ax(b+c), they have all said a(b+c)=(ab+ac), which is why you’re avoiding replying to the post of mine which quotes them all 🙄