Comment on I dunno

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SmartmanApps@programming.dev ⁨1⁩ ⁨day⁩ ago

I think I know what you’re missing - perhaps intentionally 🙄 - in a(b+c), c can be equal to 0. It can be any number, not just positive and negative, leaving us with a(b)=(axb), which is also what I’ve been saying all along (not sure how you missed it, other than to deliberately ignore it)

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