Comment on I dunno
SmartmanApps@programming.dev 1 day ago5(17) means they didn’t distribute 5(3+14) into 53+514
That’s right, they Distributed the 5(17) into (5x17), and your point is?
These textbooks unambiguously disagree
With you, yes, and your point is?
mindbleach@sh.itjust.works 1 day ago
The first textbook only gets 5(17) by not doing what the second textbook says to do with 5(3+14).
First image says ‘always simplify inside,’ and shows that.
Second image says ‘everything inside must be multiplied,’ and shows that.
You’re such an incompetent troll that you proved yourself wrong within the same post.
SmartmanApps@programming.dev 1 day ago
Because the first textbook is illustrating do brackets from the inside out, which the second textbook isn’t doing (it only has one set of brackets, not nested brackets like the first one). They even tell you that right before the example. They still are both Distributing. You’re also ignoring that they actually wrote 5[3+(14)], so they are resolving the inner brackets first, exactly as they said they were doing. 🙄 The 5 is outside the outermost brackets, and so they Distribute when they reach the outermost brackets. This is so not complicated - I don’t know why you struggle with it so much 🙄
And then says to Distribute, and shows that 🙄 “A number next to anything in brackets means the contents of the brackets should be multiplied”.
Yep, that’s right, same as I’ve been telling you the whole time 😂
Ah, no, you did, again - you even just quoted that the second one also says to Distribute! BWAHAHAHAHAHAHAHA! 😂 I’ll remember that you just called yourself an incompetent troll going forward. 😂
mindbleach@sh.itjust.works 1 day ago
You’ve harassed a dozen people to say only 5*3+5*14 is correct, to the point you think 2(3+5)^2^ isn’t 2*8^2^.
If you’d stuck to one dogmatic answer you could pretend it’s a pet peeve. But you’ve concisely proven you don’t give a shit - the harassment is the point. Quote, posture, emoji, repeat, when you can’t do algebra right.
SmartmanApps@programming.dev 1 day ago
I think I know what you’re missing - perhaps intentionally 🙄 - in a(b+c), c can be equal to 0. It can be any number, not just positive and negative, leaving us with a(b)=(axb), which is also what I’ve been saying all along (not sure how you missed it, other than to deliberately ignore it)
SmartmanApps@programming.dev 1 day ago
Nope! I’ve said a(b+c)=(ab+ac) is correct.
You mean I know that, because it disobeys The Distributive Law 🙄 The expression you’re looking for is 2x(3+5)², which is indeed not subject to Distribution, since the 2 is not next to the brackets.
Instead I’ve stuck to one actual law of Maths, a(b+c)=(ab+ac).
The Distributive Law, including c=0 🙄 Not sure why you would think c=0 is somehow an exception from a law
No, the rules of Maths is the point
Says person who thinks c=0 is somehow an exception that isn’t allowed🙄