Comment on Breaking functions down to their constituent parts is nice and all, but this is a step too far.

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AliSaket@mander.xyz ⁨6⁩ ⁨days⁩ ago

Basically the assumption is that the signal x(t) is equal to 0 for all t < 0 and that the integral converges. And what is a bit counter-intuitive: Laplace transformations can be regarded as generalizations of Fourier transformations, since the variable s is not only imaginary but fully complex. But yeah… I would have to brush up on it again, before explaining it as well. It’s… been a while.

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